Question 1024504: A problem in business statistics is given to 5 students A,B,C,D and E.
their chances of solving it are 1/2,1/3,1/4,1/5,1/6.
what is the probability that the problem will be solved.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the probability that it will be solved should be 1 minus the probability that it won't be solved.
since that is the easiest way to solve this problem, then that's the way we'll go.
the other way would be much too complex.
you would have to find the sum of the probability that the following combinations of people would solve it:
you would have to find the number of ways each could solve it by themselves.
then you would have to find the number of ways that two could solve it.
then three.
then four.
then five.
then you add them all up and you would get the probability that the problem would be solved.
the easier way is to just find the probabilility that none of them could solve it and then subtract that from 1.
that automatically gives you the probability that at least one of them could solve it.
the probabilities that each could solve it are given as:
1/2, 1/3, 1/4, 1/5, 1/6.
this means the probabilities that each could not solve it are:
1/2, 2/3, 3/4, 4/5, 5/6.
the probability that all could not solve it is therefore:
1/2 * 2/3 * 3/4 * 4/5 * 5/6 which is equal to 120/720 which is equal to 1/6.
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