Question 1024424: Please Help I have tried this problem and still getting the wrong answers. Thanks.
If ln a=2, ln b=3, and ln c=5, evaluate the following:
(a) ln(a^−4/b^1c^−4)=
(b) ln √b^−1c^−2a^2=
(c) ln(a^−2b^2)/ln(bc)^3=
(d) (ln c^−2)(ln a/b^−3)^−3=
2. If ln a=2, ln b=3, and ln c=5 , evaluate the following:
(b) ln√a^1b^4c^4=
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If ln a=2, ln b=3, and ln c=5, evaluate the following:
(a) ln(a^−4/b^1c^−4)= ln[c^4/(b*a^4)]
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= 4ln(c) - ln(b) - 4ln(a)
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= 4*5 - 3 - 4*2
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= 9
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(b) ln √(b^−1c^−2a^2)
= ln(a^2/(b*c^2))^(1/2)
----
= ln(a/(b^(1/2)*c)]
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= ln(a)- (1/2)ln(b)- ln(c)
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= 2 - (1/2)*3 -5
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= -4.5
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I'll leave the rest to you.
Cheers,
Stan H.
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(c) ln(a^−2b^2)/ln(bc)^3=
(d) (ln c^−2)(ln a/b^−3)^−3=
2. If ln a=2, ln b=3, and ln c=5 , evaluate the following:
(b) ln√a^1b^4c^4=
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