SOLUTION: factor: (2x+5)^2-(2x+5)-12 I used the substitution method: let u=2x+5 u^2-u-12 (u-4)(u+3) {(2x+5)-4}{2x+5)+3} (2x+5-4)(2x+5+3) (2x+1)(2x+8) 2(2x+1)(x+4) Is this co

Algebra ->  Expressions-with-variables -> SOLUTION: factor: (2x+5)^2-(2x+5)-12 I used the substitution method: let u=2x+5 u^2-u-12 (u-4)(u+3) {(2x+5)-4}{2x+5)+3} (2x+5-4)(2x+5+3) (2x+1)(2x+8) 2(2x+1)(x+4) Is this co      Log On


   



Question 102425: factor: (2x+5)^2-(2x+5)-12
I used the substitution method:
let u=2x+5
u^2-u-12
(u-4)(u+3)
{(2x+5)-4}{2x+5)+3}
(2x+5-4)(2x+5+3)
(2x+1)(2x+8)
2(2x+1)(x+4)
Is this correct?

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor: (2x+5)^2-(2x+5)-12
I used the substitution method:
let u=2x+5
u^2-u-12
(u-4)(u+3)
{(2x+5)-4}{2x+5)+3}
(2x+5-4)(2x+5+3)
(2x+1)(2x+8)
2(2x+1)(x+4)
Correct
===============
Cheers,
Stan H.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
yes
Very good!
Ed