SOLUTION: Predict the population of bacteria for each situation and time period. This is exponential growth. Can you help me solve for A and B?
1) 55 bacteria that double every hour after
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1) 55 bacteria that double every hour after
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Question 1024155: Predict the population of bacteria for each situation and time period. This is exponential growth. Can you help me solve for A and B?
1) 55 bacteria that double every hour after:
A) after 3 hours B) after 5 hours.
2) 33 bacteria that double every 30 minutes
A) after 1 hour B) after 6 hours. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Predict the population of bacteria for each situation and time period. This is exponential growth. Can you help me solve for A and B?
1) 55 bacteria that double every hour after:
A) after 3 hours
> 1 hour = 55*2 = 110
> 2 hour = 110*2 = 220
> 1 hour = 220*2 = 440
--> 55*2^t, t in hours
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B) after 5 hours
55*2^5 = 1760
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2) 33 bacteria that double every 30 minutes
A) after 1 hour
= 33*2^t, t in 30 min periods
= 33*2^2 = 132
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B) after 6 hours
6 hrs = 12 periods
= 33*2^12
= 135168