SOLUTION: Find 3 consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the third.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find 3 consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the third.      Log On


   

Question 1023928: Find 3 consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the third.
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
X the first number
X + 1 the second number
X + 2 the third number
4X -(X+1) = 12 + 2(X+2)
4X -X -1 = 12 + 2X + 4
3X -1 = 16 + 2X
add 1 to each side
3X = 17 + 2X
add -2X to each side
X = 17
So the numbers are 17 18 19
Verify by substituing in 4X -(X+1) = 12 + 2(X+2)
4(17) -18 = 12 + 2(19)
68 - 18 ?= 12 + 38
40 = 40