SOLUTION: Sketch two periods of {{{y = -2sin(-expr(pi/3)x)}}} I know that the amplitude is 2, and that the period is 6. What I'm having trouble with is graphing the equation. How do I split

I'm just going to draw one period.  You can extend it to two periods.
If you have trouble extending it to two periods, tell me in the
thank you note form below and I'll get back to you by email.

Draw this.  All unshifted negative sine curves look like this when
drawn for one period, beginning at the origin.


So mark the end of the period 6, and use the amplitude 2
to mark 2 and -2



Now mark the half-way point.  Half of 6 is 3.  So mark it 3.




Now you need to remember how you learned to take half of 3 in the
4th grade.

Write the 3 as 3 over 1. Multiply the tops and the bottoms.



Now mark that point half-way to 3:



Now you only have to mark the three-quarters or three-fourths
point. You just take three-fourths of 6 as you did in 4th grade.



That reduces to .  So mark that and you're done:



Now you're done with one period.  Now extend it to another period.
If you have trouble, tell me in the thank you note form below.

Edwin