SOLUTION: Julia's Boston Whaler cruised 45 miles upstream and 45 miles back in a total of 8 hours. The speed of the river is 3 mph. Find the speed of the boat in still water

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Question 1023682: Julia's Boston Whaler cruised 45 miles upstream and 45 miles back in a total of 8 hours. The speed of the river is 3 mph. Find the speed of the boat in still water
Answer by ikleyn(52781) About Me  (Show Source):
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Julia's Boston Whaler cruised 45 miles upstream and 45 miles back in a total of 8 hours. The speed of the river is 3 mph. Find the speed of the boat in still water
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Let  u  be the unknown speed of the boat in still water (in  miles per hour).

When the boat moves upstream,  its speed relative to the bank of the river is  u-3  miles per hour, 
and the time spent moving upstream is  45%2F%28u-3%29  hours. 

When the boat moves downstream,  its speed relative to the bank of the river is u%2B3  miles per hour, 
and the time spent moving downstream is  45%2F%28u%2B3%29  hours. 

So,  the total time upstream and downstream is  45%2F%28u-3%29+%2B+45%2F%28u%2B3%29,  and it is equal to  8  hours,  according to the problem's input.

This gives an equation  45%2F%28u-3%29+%2B+45%2F%28u%2B3%29+=+8. 

To simplify the equation,  multiply both sides by  %28u-3%29%2A%28u%2B3%29  and collect like terms.  Step by step,  you will get 

45%28u%2B3%29+%2B+45%28u-3%29 = 8%2A%28u%2B3%29%28u-3%29,
90u = 8%2A%28u%5E2-9%29,
90u+=+8u%5E2+-+72,
8u%5E2+-+90u+-+72 = 0.

Now cancel both sides by the factor 2. You will get

4u%5E2+-+45u+-+36 = 0.

Apply the quadratic formula

u%5B1%2C2%5D = %2845+%2B-+sqrt%2845%5E2+%2B+4%2A4%2A36%29%29%2F8 = %2845+%2B-+sqrt%282601%29%29%2F8 = %2845+%2B-+51%29%2F8.

You need only positive root u = 96%2F8 = 12.

The boat speed in still water is 12 mph.

Answer.  The boat speed in still water is  12  mile per hour.