SOLUTION: On average, a proportion of 0.48 newborns are girls. What are the chances that in a family with 4 children there are exactly three daughters. Provide answer as a proportion, roundi

Algebra ->  Probability-and-statistics -> SOLUTION: On average, a proportion of 0.48 newborns are girls. What are the chances that in a family with 4 children there are exactly three daughters. Provide answer as a proportion, roundi      Log On


   

Question 1023644: On average, a proportion of 0.48 newborns are girls. What are the chances that in a family with 4 children there are exactly three daughters. Provide answer as a proportion, rounding to two decimal places
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
This is a binomial probability problem.

The probability that in N trials, there will be
exactly x succesful outcomes, if the probability
of a success in 1 trial is p, is given by the
formula

NCx%2Ap%5Ex%2A%281-p%29%5E%28N-x%29

We seek the probability that in 4 trials, there 
will be exactly 4 succesful outcomes (girls), 
given that the probability of a success (girl) 
in 1 trial is 0.48,

4C3%2A%280.48%29%5E3%2A%281-0.48%29%5E%284-3%29

4%2A%280.110592%29%2A%280.52%29%5E1

4%2A%280.110592%29%2A%280.52%29

0.23003136

Round to 0.23, write as 23%2F100

Or do it on a TI-83 or 84 calculator.

2ND, VARS, ALPHA, MATH

If you get a screen with trials, p:, x value, Paste, 
make it read 

trials:4
p:0.48
x value:3
Paste

Highlight Paste

Press ENTER

Read:     binompdf(4,0.48,
          3)

Or if you get binompdf( make it read like that

Press ENTER

Read .23003136

Edwin