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Question 102363: You run some water into a pitcher, then cool it down by adding ice cubes.
You find that putting in 5 ice cubes cools the water down to 76°. Putting in
15 ice cubes cools the water down to 48°. Assume that the temperature of
the water varies linearly with the number of cubes you put in.
I found the equation. It is y=90-2.8x and the correlation coefficient is -1.
What temperature would the water cool to if 7 ice cubes were put in
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! You run some water into a pitcher, then cool it down by adding ice cubes.
You find that putting in 5 ice cubes cools the water down to 76°. Putting in
15 ice cubes cools the water down to 48°. Assume that the temperature of
the water varies linearly with the number of cubes you put in.
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You have two points: (5,76) and (15,48)
Equation is y = mx+b; You need to find m and b:
m= [48-76]/[15-5) = -28/10 = -2.8
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Use the point (15,48) to solve for "b":
48 = -2.8*15 + b
b = 48 + 42 = 90
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EQUATION:
temperature = -2.8*(# of cubes) + 90
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What temperature would the water cool to if 7 ice cubes were put in
temp(7) = -2.8*7 + 90
temp(7) = 70.4 degrees
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Cheers,
Stan H.
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