SOLUTION: To solve the following quadratic by completing the square, what value would you add to both sides of the equation? x^2-6x+7

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: To solve the following quadratic by completing the square, what value would you add to both sides of the equation? x^2-6x+7       Log On


   

Question 1023612: To solve the following quadratic by completing the square, what value would you add to both sides of the equation?
x^2-6x+7
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39615) About Me  (Show Source):
Answer by ikleyn(52767) About Me  (Show Source):
You can put this solution on YOUR website!
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To solve the following quadratic by completing the square, what value would you add to both sides of the equation?
x^2-6x+7
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I'd add 2.


Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

To solve the following quadratic by completing the square, what value would you add to both sides of the equation?
x^2-6x+7
This is NOT an equation, since there's no equals sign. If it were, as in: x%5E2+-+6x+%2B+7+=+0, then 9 would be ADDED to both sides to complete the square