SOLUTION: Bing rowed his boat down the river and back. Normally, in still water, he rows a constant 10 km per hour. The river had a steady current that made him faster on the way down, the

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Question 1023606: Bing rowed his boat down the river and back. Normally, in still water, he rows a constant 10 km per hour. The river had a steady current that made him faster on the way down, then slowed him down by the exact same amount on the way back. How fast was this current, if it took him 3 hours to row up and 2 hours to row back?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +c+ = the speed of the current in km/hr
+10+%2B+c+ = the speed of the boat going downstream in km/hr
+10+-+c+ = the speed of the boat going upstream in km/hr
Let +d+ = the one-way distance the boat traveled in km
----------------------------------------------
Equation for going downstream:
(1) +d+=+%28+10+%2B+c+%29%2A2+
Equation for going upstream:
(2) +d+=+%28+10+-+c+%29%2A3+
---------------------------
By substitution:
+%28+10+%2B+c+%29%2A2+=+%28+10+-+c+%29%2A3+
+20+%2B+2c+=+30+-+3c+
+5c+=+10+
+c+=+2+
The speed of the current is 2 km/hr
------------------------------
check:
(1) +d+=+%28+10+%2B+c+%29%2A2+
(1) +d+=+%28+10+%2B+2+%29%2A2+
(1) +d+=+12%2A2+
(1) +d+=+24+ km
and
(2) +d+=+%28+10+-+c+%29%2A3+
(2) +d+=+%28+10+-+2+%29%2A3+
(2) +d+=+8%2A3+
(2) +d+=+24+ km
OK