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A student has 22 coins consisting of nickles and dimes. The value of the coins is $1.50. How many dimes does she have?
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Let n = number of nickels.
Then the number of dimes is 22-n.
The "value" equation is
5n + 10*(22-n) = 150.
Simplify and solve for n:
5n + 220 - 10n = 150,
-5n = 150 - 220,
-5n = -70,
n =
= 14.
The number of nickels is 14. The number of dimes is 22-14 = 8.
Check. 5*14 + 10*8 = 70 + 80 = 150.