SOLUTION: A hollow glass cone is filled with perfume and placed inside of a hollow cylindrical container with the same height and diameter as the cone. The cylinder will then be filled with

Algebra ->  Volume -> SOLUTION: A hollow glass cone is filled with perfume and placed inside of a hollow cylindrical container with the same height and diameter as the cone. The cylinder will then be filled with       Log On


   



Question 1023475: A hollow glass cone is filled with perfume and placed inside of a hollow cylindrical container with the same height and diameter as the cone. The cylinder will then be filled with packing material. If the cone occupies 60cm cubed of space, how many cubic centimeters of packing material will be needed?
I have used the following formulas to try and figure this out.
cylinder- 3.14*r^2*h
cone- 1/3*3.14*r^2*h H= 60 D=60 R=30
what am I doing wrong?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A hollow glass cone is filled with perfume and placed inside of a hollow cylindrical container with the same height and diameter as the cone. The cylinder will then be filled with packing material. If the cone occupies 60cm cubed of space, how many cubic centimeters of packing material will be needed?
I have used the following formulas to try and figure this out.
cylinder- 3.14*r^2*h
cone- 1/3*3.14*r^2*h H= 60 D=60 R=30
what am I doing wrong?
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60 cc is the volume, not the height.
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Vol of cone = pi%2Ar%5E2%2Ah%2F3+=+60
Vol of the cylinder is 3 times that of the cone --> 180 cc
Space to be filled is 180 - 60 = 120 cc.