SOLUTION: A can of soda at 80° F. is placed in a refrigerator that maintains a constant temperature of 36° F. The temperature T of the soda t minutes after it is placed in the refrigerator i

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Question 1023373: A can of soda at 80° F. is placed in a refrigerator that maintains a constant temperature of 36° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by
T(t) = 36 + 44 e – 0.058 t
F
ind the temperature of the soda 12 minutes after it is placed in the refrigerator. (Round to the
nearest degree.)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
T%28t%29+=+36+%2B+44e%5E%28-0.058t%29
At t=12, T%2812%29+=+36+%2B+44e%5E%28-0.058%2A12%29+=+57.94 degrees Fahrenheit.