SOLUTION: Find the number of distinguishable permutations of the given letters "AAABBBCC". If a permutation is chosen at random, what is the probability that it begins with at leas

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Question 1023139: Find the number of distinguishable permutations of the given
letters "AAABBBCC".

If a permutation is chosen at random, what is the probability that it begins with at least 2 A's?

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Find the number of distinguishable permutations of the given
letters "AAABBBCC".
  
8%21%2F%283%213%212%21%29%22%22=%22%2240320%2F%286%2A6%2A2%29%22%22=%22%22560

If a permutation is chosen at random, what is the probability
that it begins with at least 2 A's?
That's the probabilility that a randomly chosen one is "AA" 
followed by a distinguishable permutation of the letters "ABBBCC".
There are 6%21%2F%283%212%21%29%22%22=%22%22720%2F%286%2A2%29%22%22=%22%2260 of these.

So the probability is that 60 times out of 560 one of those
will be chosen.  That's 60%2F560 or 3%2F28ths of the
time.

Answer: 3%2F28

Edwin