SOLUTION: http://prntscr.com/aajkcx So, I know I have to setup proportions, but could someone explain why there's a specific way you set them up? For eg, I set mine up 47/x=82.8/92 but I ge

Algebra ->  Triangles -> SOLUTION: http://prntscr.com/aajkcx So, I know I have to setup proportions, but could someone explain why there's a specific way you set them up? For eg, I set mine up 47/x=82.8/92 but I ge      Log On


   

Question 1023094: http://prntscr.com/aajkcx
So, I know I have to setup proportions, but could someone explain why there's a specific way you set them up? For eg, I set mine up 47/x=82.8/92 but I get the wrong answer. But when it's setup as 47/x=82/73.8 it gives you the right answer. So, I tried to setup as 47/x=92/73.8 it gives the wrong answer. I'm really confused why.
Answer by ikleyn(52887) About Me  (Show Source):
You can put this solution on YOUR website!
.
http://prntscr.com/aajkcx
So, I know I have to setup proportions, but could someone explain why there's a specific way you set them up? For eg, I set mine up 47/x=82.8/92 but I get the wrong answer. But when it's setup as 47/x=82/73.8 it gives you the right answer. So, I tried to setup as 47/x=92/73.8 it gives the wrong answer. I'm really confused why.
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The proportion is 47%2Fx = 92%2F82.8.

Hence, x = %2847%2A82.8%29%2F92 = 42.3.


The condition says: "The triangles are proportional".
It is very strange (and incorrect) terminology.
The triangles are SIMILAR.