SOLUTION: Log(x+1)=2logx

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Log(x+1)=2logx      Log On


   

Question 1022868: Log(x+1)=2logx
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Log(x+1) = 2logx
exponent equiv
log%28%28x%2B1%29%29=log%28%28x%5E2%29%29
therefore
x + 1 = x^2
A quadratic equation
0 = x^2 - x - 1
use the quadratic formula a=1; b=-1; c-1
Two solutions
x = -.618
x = 1.618, only solution in the original equation