SOLUTION: You can model an arch at your school using the equation y=0.7(x-3.5)(x+3.5), where x and y are both measured in feet. The x axis represents the ground. Find the width of the arch a

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: You can model an arch at your school using the equation y=0.7(x-3.5)(x+3.5), where x and y are both measured in feet. The x axis represents the ground. Find the width of the arch a      Log On


   

Question 1022841: You can model an arch at your school using the equation y=0.7(x-3.5)(x+3.5), where x and y are both measured in feet. The x axis represents the ground. Find the width of the arch at ground level.
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure how you mean, "width at ground level". Your arch is represented as a parabola, with a vertex MINIMUM. Your arch opens upward. How are you expecting your width?

Your arch as described goes below the ground.
The graph of your parabola as defined is this:
graph%28300%2C300%2C-5%2C5%2C-9%2C1%2C0.7%28x-3.5%29%28x%2B3.5%29%29



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Maybe "width" is the wrong word, and you meant "length" instead. This may be the distance between the two x-axis intercepts, being 7 feet.