SOLUTION: find three consecutive positive integers such that the product of the larger two is equal to twice the second integer plus twice the sum of all three integers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive positive integers such that the product of the larger two is equal to twice the second integer plus twice the sum of all three integers      Log On


   

Question 1022609: find three consecutive positive integers such that the product of the larger two is equal to twice the second integer plus twice the sum of all three integers
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive positive integers: (x-1), x, (x+1)

x(x+1) = 2x + 2((x-1) + x + (x+1))
x^2 + x = 2x + 6x
x^2 - 7x = 0
x(x-7) = 0
x = 0, 7

The integers are positive, so the integers are 6, 7, and 8.