SOLUTION: 2x-3y+3z=-3 6y+z=8 2x+3y+4z=9 Solve the system of equations

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Question 1022209: 2x-3y+3z=-3
6y+z=8
2x+3y+4z=9
Solve the system of equations
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
system%282x-3y%2B3z=-3%2C%0D%0A+++6y%2Bz=8%2C%0D%0A2x%2B3y%2B4z=9%29

Since x is already eliminated from the
2nd equation, we will eliminate x
from the 1st and 3rd by multiplying the
1st equation through by -1 and adding
it term by term to the 3rd equation like this:

-2x+3y-3z=3
 2x+3y+4z=9
------------
    6y+ z=12

Now we take that with the 2nd original equation
and we have a system of 2 equations in 2 unknowns:

system%28+++6y%2Bz=8%2C6y%2B+z=12%29

However we can see that if 6y+z=8, then 6y+z cannot
equal 12, so there is no solution.

This is an inconsistent system of equations.

Edwin