Question 1022098: A box contains $6.20 in quortees , dimes and nickels .there are four less Nicole's than quitters. The number of dimes is one less than twice the number of quitters . how many of each coin are there?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! let q = no. of quarters
let d = no. of dimes
let n = no. of nickels:
Write an equation for each statement\
:
A box contains $6.20 in quarters, dimes, and nickels.
.05n + .10d + .25q = 6.20
:
There are four less nickels than quarters.
n = q - 4
;
The number of dimes is one less than twice the number of quarters.
d = 2q - 1
:
in the 1st equation, replace n with (q-4), replace d with (2d-1)
.05(q-4) + .10(2q-1) + .25q = 6.20
.05q - .20 + .20q - .10 + .25q = 6.20
combine like terms
.50q - .30 = 6.20
.50q = 6.20 + .30
.50q = 6.50
q = 6.50/.50
q = 13 quarters
then
n = 13 - 4
n = 9 nickels
and
d = 2(13) - 1
d = 25 dimes
:
:
You can confirm this for yourself in the 1st equation, calculate
.05(9) + .10(25) + .25(13) =
;
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Make a little more effort in your spelling, tutors are more apt to help you.
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