SOLUTION: Find a numerical value of one trig function of X Cos^2 x + 2 sin^2 x -2=0
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Question 1022070
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Find a numerical value of one trig function of X
Cos^2 x + 2 sin^2 x -2=0
Answer by
Boreal(15235)
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cos^2 x + sin^2 x+ sin^2 x-2=0, splitting the 2 sin^2 x
the first two terms add to 1; cos^2 x+ sin^2x=1
1+sin^2 x-2=0
sin^2 x-1=0
(sin x+1)=0 (sin x-1)=0
sin x = 1 and -1