SOLUTION: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.

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Question 102205: The length of a rectangle is 2 in. more than twice its width. If the
perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
Ok first we have to know the formula for perimeter of a rectangle.
Perimeter = 2(Length) + 2(Width)
So for this rectangle lets call the width x
Width = x
Now we are told that the length is 2 in more than twice its width.
So if the width is x then
Length = 2x + 2
We are also told that the perimeter is 34 in
Ok so lets put all this into the perimeter formula and solve for x
Perimeter = 2(Length) + 2(Width)
34 = 2(2x+2) + 2(x)
34 = 4x + 4 + 2x
34 = 6x + 4
30 = 6x
5 = x
Answer: The width is 5 inches
Now use this to find the length
Length = 2x + 2
Length = 2(5) + 2
Length = 10 + 2
Length = 12
Answer: The length is 12 inches
Check answers using the perimeter formula
Perimeter = 2(Length) + 2(Width)
34 = 2(12) + 2(5)
34 = 24 + 10
34 = 34