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18mē-18x+4
That has a typo. Either the variable is m or x.
I will assuming that the variable should be m:
18mē-18m+4
Factor out GCF 2
2(9m^2-2m+2)
It factors as
2(?m??)(?m??)
where we put in signs and numbers where the
question marks are.
There is only one way to factor the +2 on
the end. as 2 and 1. So we have
2(?m?2)(?m?1)
Both signs are - since the last sign is +
and the middle sign is -.
2(?m-2)(?m-1)
The remaining two numbers must multiply to
give 9. They can only be 3 and 3, 9 and 1
or 1 and 9. Experimenting by trial and error
we get that 3 and 3 works.
2(3m-2)(3m-1)
----------------------
6x^2+7xy-10y^2
There is no common factor. Since this one
has two variables, we have this:
(?x??y)(?x??y)
and the signs must be opposite since the
last sign is -.
6 factors as 6∙1 or 3∙2. 10 factors as
10∙1, 5∙2 or 2∙5 or 10∙1
After a bit of trial and error we get
(6x-5y)(1x+2y)
Omitting the 1 coefficient
(6x-5y)(x+2y)
Edwin
