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Question 1021832: Find three consecutive odd integer such that 2 times the sum of the first two numbers is one less than thrice the third number.
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Odd integers. 1, 3, 5, etc. The difference between them is 2 (1+2=3, 3+2 = 5, etc)
So, our numbers are going to be:
x, x+2, x+2+2 = x, x+2, x+4
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2(x+x+2)= 3(x+4)-1 Multiply to get rid of parenthesis
2x+2x+4 = 3x+12-1 Add
4x+4 = 3x+11 Subtract 4 and 3x on both sides
x = 7 This is our first number.
Second number: 7+2 = 9
Third number: 9+2 = 11
Now let's check by plugging these number into the equation and finding out if we have the right answer. The problem says:
2(7+9) = 3(11)-1
32 = 32 We have the correct answer.
J
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