SOLUTION: The area of a rectangle sandbox can be expressed as 24xy + 36x. The width of the sandbox is 6x. What is the perimeter of the sandbox?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The area of a rectangle sandbox can be expressed as 24xy + 36x. The width of the sandbox is 6x. What is the perimeter of the sandbox?      Log On


   

Question 1021749: The area of a rectangle sandbox can be expressed as 24xy + 36x. The width of the sandbox is 6x. What is the perimeter of the sandbox?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
L=length; W=width=6x
.
A=LW
A/W=L
.
(24xy+36x)/6x=L
4y+6=L
.
P=2(L+W)
P=2((4y+6)+6x)
P=8y+12+12x
P=12x+8y+12
.
Perimeter is 12x+8y+12.
.