SOLUTION: points M and N are the mid-points of AC and BC, respectively. Show that d(MN) = 1/2[d(AB)]
C(b,c) A(0,0) B(a,0)
Algebra ->
Length-and-distance
-> SOLUTION: points M and N are the mid-points of AC and BC, respectively. Show that d(MN) = 1/2[d(AB)]
C(b,c) A(0,0) B(a,0)
Log On
Question 1021728: points M and N are the mid-points of AC and BC, respectively. Show that d(MN) = 1/2[d(AB)]
C(b,c) A(0,0) B(a,0) Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! If M is the midpoint of AC then it would have coordinates (b/2, c/2) by a direct application of the midpoint formula of analytic geometry. In the same way, if N is the midpoint of BC then it would have the coordinates (, c/2).
==> d(MN) =
Also,
d(AB) =
==>
