SOLUTION: Write the equation of a line that passes through (8,2) and is perpendicular to 4x-y=12

Algebra ->  College  -> Linear Algebra -> SOLUTION: Write the equation of a line that passes through (8,2) and is perpendicular to 4x-y=12      Log On


   



Question 1021706: Write the equation of a line that passes through (8,2) and is perpendicular to 4x-y=12
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
From the original equation:
.
4x-y=12
.
4x=y+12
y=4x-12 (RED LINE on graph)
.
The original slope was 4, so the slope of the perpendicular is -1/4.
.
y=(-1/4)x+b
.
Use the given point to find b (x=8, y=2):
.
2=(-1/4)(8)+b
2=-2+b
4=b
.
y=mx+b
y=(-1/4)x+4 (GREEN LINE is graph)
.
ANSWER: Equation of the perpendicular line is y=(-1/4)x+4
.
GRAPH:
.
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+4x-12%2C+%28-1%2F4%29x%2B4%29+
.