SOLUTION: The width of a rectangle is 2yd less than six times the length.The perimeter of a rectangle is 92yd.Find the dimensions.
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Question 1021689: The width of a rectangle is 2yd less than six times the length.The perimeter of a rectangle is 92yd.Find the dimensions. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Perimeter P = 2L + 2W = 92.
We also have W = 6L - 2.
Now substitute into the first equations and get
2L + 2(6L - 2) = 92
2L + 12L - 4 = 92
14L - 4 = 92
14L = 96
L = 96/14 = 6 6/7 yd
W = 6(6 6/7) - 2 = 39 1/7 yd
The dimensions are 39 1/7 yds by 6 6/7 yds.
