SOLUTION: Need to solve this by hand. Please help, thanks! How do I find the equation of the line passing through points (1,19) and (-1,-3)

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Question 1021649: Need to solve this by hand. Please help, thanks!
How do I find the equation of the line passing through points (1,19) and (-1,-3)
Found 3 solutions by macston, FrankM, ewatrrr:
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website!
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=(,)=(,)
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=(,)=(,)
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Find the slope (m):
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=
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For the equation, use slope-intercept form (y=mx+b):
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m=11
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y=11x+b
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Use either of the points or to find b:
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Using , x=1 and y=19:
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y=11x+b
19=11(1)+b
19=11+b
8=b
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Using m=11 and b=8:
y=mx+b
y=11x+8
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ANSWER: The equation is: y=11x+8
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CHECK: (Using )
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x=-1 and y=-3
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y=11x+8
-3=11(-1)+8
-3=-11+8
-3=-3
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Answer by FrankM(1040)   (Show Source):
You can put this solution on YOUR website!
The equation for slope, given 2 points:

(1,19) and (-1,-3)

Now the Point-Slope Equation, when you have a slope and a point.

m=11 (1,19)

Plug in both points and see that they fit the equation.

Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!

Hi
How do I find the equation of the line passing through points (1,19) and (-1,-3)
Takes two steps:
I. find slope m =
(1,19) and
(-1,-3 m = 22/2 = 11
II. Use y = mx + b and P(1,19)
y = 11x + b
19 = (11)(1) + b Substitute x and y values from P(1,19)
19-11 = b
8 = b
Then
y = 11x + 8 0r Standard form: 11x-y = -8