Question 1021531: Three siblings have a combined age of 108. The oldest and youngest are 8 years apart. What are the ages of the three siblings?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Three siblings have a combined age of 108.
a + b + c = 108
The oldest and youngest are 8 years apart.
a - c = 8
What are the ages of the three siblings?
Three unknowns, two equations, so let's do it this way:
divide 108 by 3 = 36; assume the middle child is 36, then oldest is 40, youngest is 32
:
40 + 36 + 32 = 108
|
|
|
