SOLUTION: How do you solve {{{4n^2/(2n+3)-(9)/(2n+3)}}}

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Question 102120: How do you solve 4n%5E2%2F%282n%2B3%29-%289%29%2F%282n%2B3%29
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(4N^2)/(2N+3)-9/(2N+3)
(4X^2+9)/2N+3)
(2N+3)(2N-3)/(2N+3) NOW CANCEL OUT THE (2N=3) TERMS.
2N-3 ANSWER.