Question 1020794: There are 3 complex numbers a+bi, c+di, and e+fi. If b=3, e=-a-c, and the sum of the numbers is 2i, find d+f.
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! From the given, a+bi = a+3i, and e+fi = a-c+fi. Together with c+di, their sum is 2a+(3+d+f)i. This sum is supposed to be equal to 2i.
Therefore, a = 0 and 3+d+f = 2, and by transposition,
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