SOLUTION: What is the equation of the circle passing through the point (6,5) and centered at (3,-4)? What are the coordinates of the center of a circle whose equation is x2 + y2 – 16x + 6

Algebra ->  Trigonometry-basics -> SOLUTION: What is the equation of the circle passing through the point (6,5) and centered at (3,-4)? What are the coordinates of the center of a circle whose equation is x2 + y2 – 16x + 6      Log On


   

Question 1020736: What is the equation of the circle passing through the point (6,5) and centered at (3,-4)?
What are the coordinates of the center of a circle whose equation is x2 + y2 – 16x + 6y + 53 = 0?
Which ordered pair is in the solution set of the system of equations shown below?
y2 – x2 + 32 = 0
3y – x = 0
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Three different questions. I will help with just the second question.

This way in pure text:
x^2+y^2–16x+6y+53=0

x%5E2%2By%5E2%9616x%2B6y%2B53=0-----in case not fully rendering, x^2+y^2-16x+6y+53=0
x%5E2-16x%2By%5E2%2B6y=-53
Choose correct terms to complete the squares as/if necessary.
x%5E2-16x%2B64%2By%5E2%2B6y%2B9=-53%2B64%2B9
%28x-8%29%5E2%2B%28y%2B3%29%5E2=73-53
highlight%28%28x-8%29%5E2%2B%28y%2B3%29%5E2=20%29
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Center point of the circle is (8,-3).


How to complete the square is described and discussed here:
http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev