SOLUTION: The floor of a rectangular room is of length 16ft. A carpet of width 9 ft. is placed so that there is a border of 1/1/2 ft. wide all around it. Calculate a.the width of the

Algebra ->  Rectangles -> SOLUTION: The floor of a rectangular room is of length 16ft. A carpet of width 9 ft. is placed so that there is a border of 1/1/2 ft. wide all around it. Calculate a.the width of the       Log On


   



Question 1020713: The floor of a rectangular room is of length 16ft. A carpet of width 9 ft. is placed so that there is a border of 1/1/2 ft. wide all around it.
Calculate
a.the width of the room
b.the area of the room
c.the area of the border

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length of the carpet = +L+ ft
The width +W+=+9+ ft
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+16+ ft = the length of the room
If I subtract the border from both ends
of the length, I get:
+16+-+2%2A%28+1.5+%29+=+16+-+3+
+16+-+3+=+13+
So, the length of the carpet, +L+=+13+
----------------
(a)
The width of the room is:
+W+%2B+2%2A%28+1.5+%29+
+9+%2B+3+=+12+
The width of the room is 12 ft
----------------
(b)
The area of the room is +16%2A12+=+192+ ft2
----------------
(c)
The area of the border is:
[ area of room ] - [ area of carpet ]
+192+-+9%2A13+=+192+-+117+
+192+-+117+=+75+
75 ft2