SOLUTION: Let f be a continuous function such that f(-1) = -1 and f(1) = 1. Classify each of the following statements as: A - ALWAYS TRUE N - NEVER TRUE S - SOMETIMES TRUE - true in some

Algebra ->  Rational-functions -> SOLUTION: Let f be a continuous function such that f(-1) = -1 and f(1) = 1. Classify each of the following statements as: A - ALWAYS TRUE N - NEVER TRUE S - SOMETIMES TRUE - true in some      Log On


   



Question 1020688: Let f be a continuous function such that f(-1) = -1 and f(1) = 1.
Classify each of the following statements as:
A - ALWAYS TRUE
N - NEVER TRUE
S - SOMETIMES TRUE - true in some cases, false in others
Justify each. Explain.
a. f(0) = 0
b. For some x with -1 <= x <= 1, f(x) = 0
c. For all x with -1 <= x < 1, -1 <= f(x) <=1
d. Given any y in [-1,1], then y = f(x) for some x in [-1,1].
e. If x < -1 or x >1, then f(x) < -1 or f(x) > 1
f . f(x) = -1 for x < 0 and f(x) = 1 for x > 0

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
a. S.
Take for example the continuous function f%28x%29+=+system%282x-1+for+x%3E=0%2C+-1+for+x%3C0%29, where f(0) = -1. On the other hand, f(x) = x gives f(0) = 0
b. A.
Since f(1) = 1 and f(-1) = -1 and f(x) is continuous, then by the intermediate value theorem, there is a c in [-1, 1] such that f(c) = 0.
c. S.
Take for example the continuous function f%28x%29+=+system%28-x-2+for+x%3C=0%2C+3x-2+for+x%3E0%29, where f(-1) = -1, f(1) = 1, but f(0) = -2. On the other hand, f(x) = x and f%28x%29+=+x%5E3 satisfy the given condition.
d. A.
This is the intermediate value theorem.
e. S.
f%28x%29+=+x%5E3 satisfies the given condition, but f%28x%29+=+x+-+x%5E3 is the complete opposite.
f. N.
In fact if it were true, the function would be discontinuous at x = 0, contradicting the hypothesis that f(x) is continuous.