SOLUTION: write an equation for the line that contains the point (8,-2) and is perpendicular to the line 4x-2y=9

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Question 1020378: write an equation for the line that contains the point (8,-2) and is perpendicular to the line 4x-2y=9
Found 2 solutions by robertb, josgarithmetic:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The line would have the form 2x+4y = c for some particular constant c.
c = 2*8 + 4*(-2) = 16 - 8 = 8.
Therefore the line is 2x+4y = 8, or x + 2y = 4.

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
4x-2y=9
-2y=-4x%2B9
y=2x-9%2F2
Slope is 2.

Any line perpendicular to the given line must have slope -1%2F2. Such a line to pass through (8,-2), using the point-slope equation form, will be y-%28-2%29=-%281%2F2%29%28x-8%29. Do what you need or want from this form.