Question 1020365: A woman earns $2,100 in interest from two accounts in a year. If she has three times as much invested at 8% as she does at 6%, how much does she have in each account?
I know I have to make a systems of equations, and I have 2,100=3a+b but im not sure if thats right or what the other one would be
Answer by MathTherapy(10555)   (Show Source):
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A woman earns $2,100 in interest from two accounts in a year. If she has three times as much invested at 8% as she does at 6%, how much does she have in each account?
I know I have to make a systems of equations, and I have 2,100=3a+b but im not sure if thats right or what the other one would be
Let amounts invested in 8% and 6% funds, be E, and S, respectively
Then equation for amounts invested is: E = 3S
Interest equation: .08E + .06S = 2,100
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