Question 1020294: A train leaves Orlando at 2:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels 54 mph faster than the first. If the second train overtakes the first at 8:00 PM, what is the speed of each of the two trains?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A train leaves Orlando at 2:00 PM.
A second train leaves the same city in the same direction at 5:00 PM.
The second train travels 54 mph faster than the first.
If the second train overtakes the first at 8:00 PM, what is the speed of each of the two trains?
:
When one train overtakes the other, they will have traveled the same distance
:
let s = the speed of the first train
then
(s+54) = the speed of the 2nd train
:
From the information given we know.
6 hrs is the travel time of the 1st train
3 hrs is the travel time of the 2nd train
:
Write a distance equation, dist = time * speed
6s = 3(s+54)
6s = 3s + 162
6s - 3s = 162
3s = 162
s = 162/3
s = 54 mph is the speed of the 1st train
then
54 + 54 = 108 mph is the speed of the 2nd train
:
;
Makes sense; the 2nd train takes half as long as the first train because it goes twice as fast.
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