SOLUTION: Mo and Jo have a total of 120 coins. Bo and KO have 153; and Mo and Bo have 127. How many coins do Jo and Ko have, in all?
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Question 1020163
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Mo and Jo have a total of 120 coins. Bo and KO have 153; and Mo and Bo have 127. How many coins do Jo and Ko have, in all?
Answer by
CubeyThePenguin(3113)
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M + J = 120
B + K = 153
M + B = 127
Add all equations: 2M + 2B + J + K = 400
2(M + B) + J + K = 400
2(127) + J + K = 400
J + K = 146
Jo and Ko have 146 coins in total.