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Use the substitution method to solve the following system of equations.
(1) 3x + 4y = 8
(2) x/4 + y/3 = 1
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3x + 4y = 8, (1)
x/4 + y/3 = 1. (2)
Multiply equation (2) by 3*4 = 12 (both sides). You will get
3x + 4y = 12 (3)
instead of (2).
Now you have this system of two equations
3x + 4y = 8, (1)
3x + 4y = 12. (3)
Their left side are identical, while right sides are different,
It means that the system has no solution.
