Question 1019936: A rock is thrown upward with a velocity of 26 meters per second from the top of a 43 meter high cliff, and it misses the cliff on the way back down. When will the rock be 6 meters from the water, below? Round your answer to two decimal places.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A rock is thrown upward with a velocity of 26 meters per second from the top of a 43 meter high cliff, and it misses the cliff on the way back down. When will the rock be 6 meters from the water, below? Round your answer to two decimal places.
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h(t) = -4.9t^2 + 26t + 43
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Solve::
-4.9t^2 + 26t + 43 = 6
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-4.9t^2 + 26t + 37 = 0
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Solve for "t":
t = 6.473 seconds
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Cheers,
Stan H.
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