SOLUTION: Given that z is a standard normal random variable, find z for each situation. a) The area to the left of z is 0.9750. b) The area between 0 and z is 0.4750. c) The area to th

Algebra ->  Probability-and-statistics -> SOLUTION: Given that z is a standard normal random variable, find z for each situation. a) The area to the left of z is 0.9750. b) The area between 0 and z is 0.4750. c) The area to th      Log On


   



Question 1019931: Given that z is a standard normal random variable, find z for each situation.
a) The area to the left of z is 0.9750.
b) The area between 0 and z is 0.4750.
c) The area to the left of z is 0.7291.
d) The area to the right of z is 0.1314.
e) The area to the left of z is 0.6700.
f) The area to the right of z is 0.3300.
Answers:
a) z = 1.96
b) z = 1.96
c) z = 0.61
d) z = 1.12
e) z = 0.44
f) z = 0.44

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Given that z is a standard normal random variable,
find z for each situation.
Instead of doing your problem for you, I've drawn the normal
curve graphs, and shaded the area mentioned.  All you have to
do is look on the z-axis of each graph and find which value on
your list of answers is closest to the z-score along that z-axis 
where the shading stops or starts, depending on whether the area 
is to the left or to the right. Here are the shaded graphs:

a) The area to the left of z is 0.9750. 



b) The area between 0 and z is 0.4750.



c) The area to the left of z is 0.7291.



d) The area to the right of z is 0.1314. 



e) The area to the left of z is 0.6700.




 
f) The area to the right of z is 0.3300. 



Answers: 
a) z = 1.96 
b) z = 1.96 
c) z = 0.61 
d) z = 1.12 
e) z = 0.44 
f) z = 0.44

Edwin