SOLUTION: What is the solution set of the inequality {{{log(1/3,x^2+3x+4) <= -1}}}?

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Question 1019829: What is the solution set of the inequality log%281%2F3%2Cx%5E2%2B3x%2B4%29+%3C=+-1?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
log%281%2F3%2C%28x%5E2%2B3x%2B4%29%29+%3C=+-1

Let the left side = y

log%281%2F3%2C%28x%5E2%2B3x%2B4%29%29+=+y

%281%2F3%29%5Ey+=+x%5E2%2B3x%2B4

Take the log base 10 of both sides

log%28%281%2F3%29%5Ey%29+=+log%28%28x%5E2%2B3x%2B4%29%29

y%2Alog%28%281%2F3%29%29+=+log%28%28x%5E2%2B3x%2B4%29%29

y+=+log%28%28x%5E2%2B3x%2B4%29%29%2Flog%28%281%2F3%29%29

The original inequality was

log%281%2F3%2C%28x%5E2%2B3x%2B4%29%29+%3C=+-1

So y%3C=-1.  Substituting for y

log%28%28x%5E2%2B3x%2B4%29%29%2Flog%28%281%2F3%29%29%3C=-1

We know that log%28%281%2F3%29%29=-.4771 is a negative 
number, so when we multiply both sides
of the inequality by it, the inequality
symbol will reverse:

log%28%28x%5E2%2B3x%2B4%29%29%3E=-1%2Alog%28%281%2F3%29%29

Use a principle of logarithms to rewrite
the right side:

log%28%28x%5E2%2B3x%2B4%29%29%3E=log%28%28%281%2F3%29%5E%28-1%29%29%29

Since raising to the -1 power is the same
as taking the rciprocal, the above becomes:

log%28%28x%5E2%2B3x%2B4%29%29%3E=log%28%283%29%29

Since logs base 10 are in ascending order,

x%5E2%2B3x%2B4%3E=3

x%5E2%2B3x%2B1%3E=0

That has critical numbers

 x+=+%28-3+%2B-+sqrt%28+3%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29+

 x+=+%28-3+%2B-+sqrt%285%29%29%2F2+

Put those two values on a number line and
choose a test point in each region to discover that
the solution set is

 x+%3C=+%28-3+-+sqrt%285%29%29%2F2+ or x+%3E=%28-3+%2B+sqrt%285%29%29%2F2+

Edwin