SOLUTION: Solve for x, check for any extraneous solutions. sqrt(2x+1) -8= -5 I got x=-5 and x=4. I don't know if this correct. Please help me clarify this. Thanks!

Algebra ->  Rational-functions -> SOLUTION: Solve for x, check for any extraneous solutions. sqrt(2x+1) -8= -5 I got x=-5 and x=4. I don't know if this correct. Please help me clarify this. Thanks!       Log On


   



Question 1019753: Solve for x, check for any extraneous solutions.
sqrt(2x+1) -8= -5
I got x=-5 and x=4. I don't know if this correct. Please help me clarify this. Thanks!

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x, check for any extraneous solutions.
sqrt(2x+1) -8= -5
I got x=-5 and x=4.
You apparently know how to solve equations with 
square roots. You only need to learn how to check 
your answers. You must always check answers in 
equations containing square roots, for they often
give bogus solutions.

sqrt%282x%2B1%29+-8=+-5

Let's check your first answer x=-5

sqrt%282%28-5%29%2B1%29+-8=+-5

sqrt%28-10%2B1%29+-8=+-5

sqrt%28-9%29+-8=+-5

That has a neative number under a square root,
so it cannot be a real number. So -5 is an
extraneous solution.  So we discard it.

sqrt%282x%2B1%29+-8=+-5

Let's check your second answer x=4

sqrt%282%284%29%2B1%29+-8=+-5

sqrt%288%2B1%29+-8=+-5

sqrt%289%29+-8=+-5

3+-8=+-5

-5=+-5

That one checks.  So x = 4 is the only
solution.

Edwin