SOLUTION: Find three consecutive even integers such that three times the first equals the sum of the other two.

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Question 1019629: Find three consecutive even integers such that three times the first equals the sum of the other two.

Found 3 solutions by Alan3354, josgarithmetic, solver91311:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
Find three consecutive even integers such that three times the first equals the sum of the other two.
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3n = n+2 + n+4
--> 6, 8 & 10

Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website!
n, any integer;]
2n, an even integer;
2n+2 and 2n+4 are the consecutive even integers greater than 2n.

The transcribed description: .

Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!

Let represent the first of the three consecutive even integers. Then is the second one and is the third. You are given that

Solve for , then calculate and

John

My calculator said it, I believe it, that settles it