SOLUTION: Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to c
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Question 1019528: Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 day? Found 2 solutions by robertb, MathTherapy:Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! The total number of man hours (for the first 6 days) required to finish 5/21 of the work is 10*6*10 = 600 man-hours. Hence each man contributes for the entire job.
Now 16/21 of the job still had to be done, and the job had to be done at the same rate and at the same number of hours each day.
Note that 16/21 of the job had to be completed in 2 more days. (2 additional days after initial 6 days.)
Let m = number of men required to complete the job in two more days
Hence...
==>
==> m = 96.
Therefore it will take 96 men to finish the job in two more days at the same rate and same number of hours each day.
You can put this solution on YOUR website!
Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 day?
It'll take men, working 8 days, @ 10 hours each day, or 80 hours to complete the remaining of job
