SOLUTION: 56x^4yz^12 ___________ 14x^9y^2z^4 *the entire problem is inside of a square root sign.

Algebra ->  Radicals -> SOLUTION: 56x^4yz^12 ___________ 14x^9y^2z^4 *the entire problem is inside of a square root sign.       Log On


   

Question 101947: 56x^4yz^12
___________
14x^9y^2z^4

*the entire problem is inside of a square root sign.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Do you mean like this sqrt%2856%2Ax%5E4%2Ay%2Az%5E12%2F14x%5E9y%5E2z%5E4%29?
If so, when you divide the same base, you subtract exponents and when you multiply the same base you add exponents. If you have an exponent expression raised to a power, you multiply the exponent and power.
%28W%5Em%29%2A%28W%5En%29+=+W%5E%28m%2Bn%29
%28W%5Em%29%2F%28W%5En%29+=+W%5E%28m-n%29
%28W%5Em%29%5En+=+W%5E%28m%2An%29
%28U%5Em%2AW%5En%29%5Ep+=+U%5E%28m%2Ap%29%2AW%5E%28n%2Ap%29
Now back to the problem.
sqrt%2856%2Ax%5E4%2Ay%2Az%5E12%2F14x%5E9y%5E2z%5E4%29
sqrt%2856%2Ax%5E%284-9%29%2Ay%5E%281-2%29%2Az%5E%2812-4%29%2F14%29 Add and subtract exponents.
sqrt%284%2Ax%5E%28-5%29%2Ay%5E%28-1%29%2Az%5E%288%29%29 Simplify.
%284%2Ax%5E%28-5%29%2Ay%5E%28-1%29%2Az%5E%288%29%29%5E%281%2F2%29 Rewrite square root as power of 1/2.
2%2Ax%5E%28-5%2F2%29%2Ay%5E%28-1%2F2%29%2Az%5E%284%29 Multiply exponents and powers.
2%2Az%5E4%2Fsqrt%28x%5E%285%29%2Ay%29%29 Simplify and re-write.