SOLUTION: The perimeter of a rectangle is 74 ft. The length is 7 ft more than twice the width. What are the dimensions of the rectangle?
Algebra ->
Equations
-> SOLUTION: The perimeter of a rectangle is 74 ft. The length is 7 ft more than twice the width. What are the dimensions of the rectangle?
Log On
Question 101938: The perimeter of a rectangle is 74 ft. The length is 7 ft more than twice the width. What are the dimensions of the rectangle? Answer by brianuh(2) (Show Source):
You can put this solution on YOUR website! p = l X w
l = 2w +7
74 = w X 2w + 7
67 = 3w
67/3 = 22.3
22.3 = w
l = 22.3 X 2 + 7
l = 89.3
w = 22.3
(