SOLUTION: 1)the roots of a parabola are 5 and -7. what is the equation of the parabola? 2) what is the axis of symmetry for the parabola y=-1/16(x+4)^2-7?

Algebra ->  Graphs -> SOLUTION: 1)the roots of a parabola are 5 and -7. what is the equation of the parabola? 2) what is the axis of symmetry for the parabola y=-1/16(x+4)^2-7?      Log On


   



Question 1019318: 1)the roots of a parabola are 5 and -7. what is the equation of the parabola?
2) what is the axis of symmetry for the parabola y=-1/16(x+4)^2-7?

Answer by ikleyn(52781) About Me  (Show Source):
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1)the roots of a parabola are 5 and -7. what is the equation of the parabola?
2) what is the axis of symmetry for the parabola y=-1/16(x+4)^2-7?
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1) the roots of a parabola are 5 and -7. what is the equation of the parabola?

The equation of the parabola is

y = (x-5)*(x-(-7)),   or, which is the same,

y = (x-5)*(x+7)


2) what is the axis of symmetry for the parabola y=-1/16(x+4)^2-7?

The axis of symmetry for this parabola is vertical line x = -4.